Measure Theoretic Probability - Video 7.1 - Algebra Basics
Algebra Basics
The only algebra on \(\Omega=\emptyset\) is the collection \(\Omega\).
The only algebra on \(\Omega=\{1\}\) is the collection \(\emptyset,\Omega\).
The only two algebras on \(\Omega=\{1,2\}\) are \(\emptyset,\Omega\) and \(\mathcal P(\Omega)\).
There are exactly five algebras on \(\Omega=\{1,2,3\}\).
\(\emptyset,\Omega\)
\(\mathcal P(\Omega)\)
\(\{\emptyset,\{1\},\{2,3\},\Omega\}\)
\(\{\emptyset,\{2\},\{1,3\},\Omega\}\)
\(\{\emptyset,\{3\},\{1,2\},\Omega\}\)
Max and Min
We call \(\{\emptyset,\Omega\}\) the minimal algebra on \(\Omega\). We call \(\mathcal P(\Omega)\) the maximal algebra on \(\Omega\). These are both always algebras for any set \(\Omega\).
Proof: \(\mathcal P(\Omega)\) always satisfies every containment requirement because it contains everything. Therefore, trivially, this satisfies the conditions for being an algebra.
To check that \(\{\emptyset,\Omega\}\) is an algebra, trivially it contains the universe. It is closed under complements because \(\emptyset^c=\Omega\in\{\emptyset,\Omega\}\) and \(\Omega^c=\emptyset\in\{\emptyset,\Omega\}\). It is closed under unions because
\(\emptyset\cup\emptyset=\emptyset \in\{\emptyset,\Omega\}\)
\(\emptyset\cup\Omega=\Omega\cup\emptyset=\Omega\in\{\emptyset,\Omega\}\)
\(\Omega\cup\Omega=\Omega\in\{\emptyset,\Omega\}\)