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Strong convergence in L2(E) if this limit and integral exchange

Theorem: (Royden Real Analysis 4th ed. Section 8.2 Problem 16)

Suppose that E is a measurable set and every function in sight lives in L2(E). Further suppose

limEfnfEf2=limEfn2

Then {fn}f strongly in L2(E).

Proof:

E(fnf)2=Efn22Effn+Ef2

Which has limit zero by the assumptions of the problem.